Square pyramid
Find volume, slant height and surface area of a right square pyramid.
Find the radius of the circle passing through all three triangle vertices.
Find the radius of the circle passing through all three triangle vertices.
Triangle side a: 3; Triangle side b: 4; Triangle side c: 5.
Circumcircle radius: 2.5 units; Circumcircle diameter: 5 units.
All three side lengths must form a nondegenerate triangle. The circumcircle passes through the three vertices; its radius differs from the incircle radius.
Results are rounded for display; calculations use unrounded values. Read our calculation methodology.
Find the radius of the circle passing through all three triangle vertices.
Circumcircle radius = a*b*c/(4*sqrt((a+b+c)/2*((a+b+c)/2-a)*((a+b+c)/2-b)*((a+b+c)/2-c))) units; Circumcircle diameter = a*b*c/(2*sqrt((a+b+c)/2*((a+b+c)/2-a)*((a+b+c)/2-b)*((a+b+c)/2-c))) units
| Input | What to enter |
|---|---|
| Triangle side a | Enter a number of at least 1e-12 and no more than 1000000000000. |
| Triangle side b | Enter a number of at least 1e-12 and no more than 1000000000000. |
| Triangle side c | Enter a number of at least 1e-12 and no more than 1000000000000. |
All three side lengths must form a nondegenerate triangle. The circumcircle passes through the three vertices; its radius differs from the incircle radius.
Circumcircle radius = a*b*c/(4*sqrt((a+b+c)/2*((a+b+c)/2-a)*((a+b+c)/2-b)*((a+b+c)/2-c))) units; Circumcircle diameter = a*b*c/(2*sqrt((a+b+c)/2*((a+b+c)/2-a)*((a+b+c)/2-b)*((a+b+c)/2-c))) units