Heat conduction through a slab
Estimate steady heat conduction through one flat homogeneous layer.
Estimate steady conductive heat flow through two flat layers in series.
Estimate steady conductive heat flow through two flat layers in series.
L1/(k1*A)+L2/(k2*A) K/WdT/(L1/(k1*A)+L2/(k2*A)) WThis is an ideal educational model. Enter quantities in the stated SI units; it does not certify equipment safety or real operating limits. Excludes contact resistance, convection, radiation, thermal bridges and transient heat storage.
Results are rounded for display; calculations use unrounded values. Read our calculation methodology.
Estimate steady conductive heat flow through two flat layers in series. Layer resistance depends on thickness, conductivity and common wall area. A negative temperature difference reverses heat flow.
Layer resistance depends on thickness, conductivity and common wall area. A negative temperature difference reverses heat flow.
| Input | Example |
|---|---|
Wall area (m²) A | 10 |
First layer thickness (m) L1 | 0.1 |
First thermal conductivity (W/m·K) k1 | 0.5 |
Second layer thickness (m) L2 | 0.05 |
Second thermal conductivity (W/m·K) k2 | 0.04 |
Temperature difference (K) dT | 20 |
This is an ideal educational model. Enter quantities in the stated SI units; it does not certify equipment safety or real operating limits. Excludes contact resistance, convection, radiation, thermal bridges and transient heat storage.
Use the displayed example inputs in the stated formula. Keep each quantity in its labelled unit and compare the unrounded result before applying display rounding.